Optimal. Leaf size=110 \[ \frac{8 e^2 (d-e x)}{d \sqrt{d^2-e^2 x^2}}+\frac{4 e \sqrt{d^2-e^2 x^2}}{d x}-\frac{\sqrt{d^2-e^2 x^2}}{2 x^2}-\frac{15 e^2 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )}{2 d} \]
[Out]
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Rubi [A] time = 0.412657, antiderivative size = 110, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 7, integrand size = 27, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.259 \[ \frac{8 e^2 (d-e x)}{d \sqrt{d^2-e^2 x^2}}+\frac{4 e \sqrt{d^2-e^2 x^2}}{d x}-\frac{\sqrt{d^2-e^2 x^2}}{2 x^2}-\frac{15 e^2 \tanh ^{-1}\left (\frac{\sqrt{d^2-e^2 x^2}}{d}\right )}{2 d} \]
Antiderivative was successfully verified.
[In] Int[(d^2 - e^2*x^2)^(5/2)/(x^3*(d + e*x)^4),x]
[Out]
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Rubi in Sympy [A] time = 33.3633, size = 88, normalized size = 0.8 \[ - \frac{\sqrt{d^{2} - e^{2} x^{2}}}{2 x^{2}} - \frac{15 e^{2} \operatorname{atanh}{\left (\frac{\sqrt{d^{2} - e^{2} x^{2}}}{d} \right )}}{2 d} + \frac{8 e^{2} \sqrt{d^{2} - e^{2} x^{2}}}{d \left (d + e x\right )} + \frac{4 e \sqrt{d^{2} - e^{2} x^{2}}}{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((-e**2*x**2+d**2)**(5/2)/x**3/(e*x+d)**4,x)
[Out]
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Mathematica [A] time = 0.200272, size = 85, normalized size = 0.77 \[ \frac{\frac{\sqrt{d^2-e^2 x^2} \left (-d^2+7 d e x+24 e^2 x^2\right )}{x^2 (d+e x)}-15 e^2 \log \left (\sqrt{d^2-e^2 x^2}+d\right )+15 e^2 \log (x)}{2 d} \]
Antiderivative was successfully verified.
[In] Integrate[(d^2 - e^2*x^2)^(5/2)/(x^3*(d + e*x)^4),x]
[Out]
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Maple [B] time = 0.021, size = 504, normalized size = 4.6 \[ -{\frac{1}{2\,{d}^{6}{x}^{2}} \left ( -{e}^{2}{x}^{2}+{d}^{2} \right ) ^{{\frac{7}{2}}}}+{\frac{3\,{e}^{2}}{2\,{d}^{6}} \left ( -{e}^{2}{x}^{2}+{d}^{2} \right ) ^{{\frac{5}{2}}}}+{\frac{5\,{e}^{2}}{2\,{d}^{4}} \left ( -{e}^{2}{x}^{2}+{d}^{2} \right ) ^{{\frac{3}{2}}}}+{\frac{15\,{e}^{2}}{2\,{d}^{2}}\sqrt{-{e}^{2}{x}^{2}+{d}^{2}}}-{\frac{15\,{e}^{2}}{2}\ln \left ({\frac{1}{x} \left ( 2\,{d}^{2}+2\,\sqrt{{d}^{2}}\sqrt{-{e}^{2}{x}^{2}+{d}^{2}} \right ) } \right ){\frac{1}{\sqrt{{d}^{2}}}}}-4\,{\frac{{e}^{2}}{{d}^{6}} \left ( - \left ( x+{\frac{d}{e}} \right ) ^{2}{e}^{2}+2\,de \left ( x+{\frac{d}{e}} \right ) \right ) ^{5/2}}-5\,{\frac{{e}^{3}x}{{d}^{5}} \left ( - \left ( x+{\frac{d}{e}} \right ) ^{2}{e}^{2}+2\,de \left ( x+{\frac{d}{e}} \right ) \right ) ^{3/2}}-{\frac{15\,{e}^{3}x}{2\,{d}^{3}}\sqrt{- \left ( x+{\frac{d}{e}} \right ) ^{2}{e}^{2}+2\,de \left ( x+{\frac{d}{e}} \right ) }}-{\frac{15\,{e}^{3}}{2\,d}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{- \left ( x+{\frac{d}{e}} \right ) ^{2}{e}^{2}+2\,de \left ( x+{\frac{d}{e}} \right ) }}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}}+4\,{\frac{e \left ( -{e}^{2}{x}^{2}+{d}^{2} \right ) ^{7/2}}{{d}^{7}x}}+4\,{\frac{{e}^{3}x \left ( -{e}^{2}{x}^{2}+{d}^{2} \right ) ^{5/2}}{{d}^{7}}}+5\,{\frac{{e}^{3}x \left ( -{e}^{2}{x}^{2}+{d}^{2} \right ) ^{3/2}}{{d}^{5}}}+{\frac{15\,{e}^{3}x}{2\,{d}^{3}}\sqrt{-{e}^{2}{x}^{2}+{d}^{2}}}+{\frac{15\,{e}^{3}}{2\,d}\arctan \left ({x\sqrt{{e}^{2}}{\frac{1}{\sqrt{-{e}^{2}{x}^{2}+{d}^{2}}}}} \right ){\frac{1}{\sqrt{{e}^{2}}}}}-2\,{\frac{1}{{d}^{6}} \left ( - \left ( x+{\frac{d}{e}} \right ) ^{2}{e}^{2}+2\,de \left ( x+{\frac{d}{e}} \right ) \right ) ^{7/2} \left ( x+{\frac{d}{e}} \right ) ^{-2}}+{\frac{1}{{d}^{4}{e}^{2}} \left ( - \left ( x+{\frac{d}{e}} \right ) ^{2}{e}^{2}+2\,de \left ( x+{\frac{d}{e}} \right ) \right ) ^{{\frac{7}{2}}} \left ( x+{\frac{d}{e}} \right ) ^{-4}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((-e^2*x^2+d^2)^(5/2)/x^3/(e*x+d)^4,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac{5}{2}}}{{\left (e x + d\right )}^{4} x^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-e^2*x^2 + d^2)^(5/2)/((e*x + d)^4*x^3),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.281926, size = 405, normalized size = 3.68 \[ \frac{40 \, e^{5} x^{5} - 17 \, d e^{4} x^{4} - 102 \, d^{2} e^{3} x^{3} + 21 \, d^{3} e^{2} x^{2} + 30 \, d^{4} e x - 4 \, d^{5} + 15 \,{\left (e^{5} x^{5} + 3 \, d e^{4} x^{4} - 2 \, d^{2} e^{3} x^{3} - 4 \, d^{3} e^{2} x^{2} -{\left (e^{4} x^{4} - 2 \, d e^{3} x^{3} - 4 \, d^{2} e^{2} x^{2}\right )} \sqrt{-e^{2} x^{2} + d^{2}}\right )} \log \left (-\frac{d - \sqrt{-e^{2} x^{2} + d^{2}}}{x}\right ) +{\left (8 \, e^{4} x^{4} + 87 \, d e^{3} x^{3} - 19 \, d^{2} e^{2} x^{2} - 30 \, d^{3} e x + 4 \, d^{4}\right )} \sqrt{-e^{2} x^{2} + d^{2}}}{2 \,{\left (d e^{3} x^{5} + 3 \, d^{2} e^{2} x^{4} - 2 \, d^{3} e x^{3} - 4 \, d^{4} x^{2} -{\left (d e^{2} x^{4} - 2 \, d^{2} e x^{3} - 4 \, d^{3} x^{2}\right )} \sqrt{-e^{2} x^{2} + d^{2}}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-e^2*x^2 + d^2)^(5/2)/((e*x + d)^4*x^3),x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-e**2*x**2+d**2)**(5/2)/x**3/(e*x+d)**4,x)
[Out]
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GIAC/XCAS [A] time = 0.338371, size = 1, normalized size = 0.01 \[ \mathit{Done} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((-e^2*x^2 + d^2)^(5/2)/((e*x + d)^4*x^3),x, algorithm="giac")
[Out]